you can pass it as a function parameterĮ.g.: > print(ObjectCreator) # you can print a class because it's an object.This object (the class) is itself capable of creating objects (the instances),īut still, it's an object, and therefore: The instruction > class ObjectCreator(object):Ĭreates in memory an object with the name ObjectCreator. Classes are objects too.Īs soon as you use the keyword class, Python executes it and createsĪn object. That's kinda true in Python too: > class ObjectCreator(object):īut classes are more than that in Python. In most languages, classes are just pieces of code that describe how to produce an object. And Python has a very peculiar idea of what classes are, borrowed from the Smalltalk language. My_abs_path = my_file.resolve(strict=True)īefore understanding metaclasses, you need to master classes in Python. You can also use resolve(strict=True) in a try block: try: To check whether a Path object exists independently of whether is it a file or directory, use exists(): if my_file.exists(): To check a directory, do: if my_file.is_dir(): Starting with Python 3.4, the pathlib module offers an object-oriented approach (backported to pathlib2 in Python 2.7): from pathlib import Path This follows symbolic links, so both islink() and isfile() can be true for the same path. Return True if path is an existing regular file. If you're not planning to open the file immediately, you can use os.path.isfile Checking and then opening risks the file being deleted or moved or something between when you check and when you try to open it. If the reason you're checking is so you can do something like if file_exists: open_it(), it's safer to use a try around the attempt to open it.
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